## JEE Advanced 2016 Paper 1 Mathematics Question 53

Let $\alpha, \beta \in \mathbb{R}$ be such that $\displaystyle\lim_{x \rightarrow 0} \frac{x^2 \text{sin} (\beta{x})}{\alpha{x} - \text{sin}x} = 1$. Then $6(\alpha + \beta)$ equals

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